Page 76 - Engineering Electromagnetics, 8th Edition
P. 76

58                 ENGINEERING ELECTROMAGNETICS






















                                                         Figure 3.4 The gaussian
                                                         surface for an infinite uniform line
                                                         charge is a right circular cylinder of
                                                         length L and radius ρ. D is
                                                         constant in magnitude and
                                                         everywhere perpendicular to the
                                                         cylindrical surface; D is parallel to
                                                         the end faces.

                                     giving

                                                                        ρ L
                                                                  D ρ =
                                                                       2πρ
                                     or

                                                                        ρ L
                                                                 E ρ =
                                                                      2π  0 ρ
                                        Comparing with Section 2.4, Eq. (16), shows that the correct result has been
                                     obtained and with much less work. Once the appropriate surface has been chosen, the
                                     integration usually amounts only to writing down the area of the surface at which D
                                     is normal.
                                        The problem of a coaxial cable is almost identical with that of the line charge and
                                     is an example that is extremely difficult to solve from the standpoint of Coulomb’s
                                     law. Suppose that we have two coaxial cylindrical conductors, the inner of radius a
                                     and the outer of radius b, each infinite in extent (Figure 3.5). We will assume a charge
                                     distribution of ρ S on the outer surface of the inner conductor.
                                        Symmetry considerations show us that only the D ρ component is present and
                                     that it can be a function only of ρ.A right circular cylinder of length L and radius ρ,
                                     where a <ρ < b,is necessarily chosen as the gaussian surface, and we quickly have

                                                                 Q = D S 2πρL
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