Page 80 - Engineering Electromagnetics, 8th Edition
P. 80

62                 ENGINEERING ELECTROMAGNETICS






















                                                  Figure 3.6 A differential-sized gaussian surface about
                                                  the point P is used to investigate the space rate of
                                                  change of D in the neighborhood of P.


                                     where D x0 is the value of D x at P, and where a partial derivative must be used to
                                     express the rate of change of D x with x,as D x in general also varies with y and z.
                                     This expression could have been obtained more formally by using the constant term
                                     and the term involving the first derivative in the Taylor’s-series expansion for D x in
                                     the neighborhood of P.
                                        We now have


                                                                          x ∂D x
                                                                ˙ =  D x0 +       y  z
                                                            front         2 ∂x
                                        Consider now the integral over the back surface,

                                                                ˙ = D back ·  S back
                                                            back
                                                                ˙ = D back · (− y  z a x )
                                                                ˙ =−D x,back  y  z
                                     and
                                                                          x ∂D x
                                                           D x,back ˙= D x0 −
                                                                         2   ∂x
                                     giving



                                                                           x ∂D x
                                                                ˙ =  −D x0 +        y  z
                                                            back           2   ∂x
                                     If we combine these two integrals, we have

                                                                       ∂D x
                                                              +      ˙ =   x  y  z
                                                           front  back  ∂x
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