Page 92 - Engineering Electromagnetics, 8th Edition
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74                 ENGINEERING ELECTROMAGNETICS

                                     3.24 In a region in free space, electric flux density is found to be
                                                           ρ 0 (z + 2d) a z C/m  (−2d ≤ z ≤ 0)
                                                          
                2
                                                      D =
                                                           −ρ 0 (z − 2d) a z C/m 2  (0 ≤ z ≤ 2d)
                                          Everywhere else, D = 0. (a) Using ∇· D = ρ v , find the volume charge
                                          density as a function of position everywhere. (b) Determine the electric flux
                                          that passes through the surface defined by z = 0, −a ≤ x ≤ a, −b ≤ y ≤ b.
                                          (c) Determine the total charge contained within the region −a ≤ x ≤ a,
                                          −b ≤ y ≤ b, −d ≤ z ≤ d.(d) Determine the total charge contained within
                                          the region −a ≤ x ≤ a, −b ≤ y ≤ b,0 ≤ z ≤ 2d.

                                     3.25 Within the spherical shell, 3 < r < 4m, the electric flux density is given as
                                                     3
                                                            2
                                          D = 5(r − 3) a r C/m .(a) What is the volume charge density at r = 4?
                                          (b) What is the electric flux density at r = 4? (c)How much electric flux
                                          leaves the sphere r = 4? (d)How much charge is contained within the sphere
                                          r = 4?
                                                                                  3
                                     3.26 If we have a perfect gas of mass density ρ m kg/m , and we assign a
                                          velocity U m/s to each differential element, then the mass flow rate is
                                                    2
                                          ρ m U kg/(m − s). Physical reasoning then leads to the continuity equation,
                                          ∇ · (ρ m U) =−∂ρ m /∂t.(a) Explain in words the physical interpretation of
                                          this equation. (b) Show that  	 s  ρ m U · dS =−dM/dt, where M is the total
                                          mass of the gas within the constant closed surface S, and explain the physical
                                          significance of the equation.
                                                                                                  2
                                                              2
                                                      2
                                                                                            2
                                     3.27 Let D = 5.00r a r mC/m for r ≤ 0.08 m and D = 0.205 a r /r µC/m for
                                          r ≥ 0.08 m. (a) Find ρ ν for r = 0.06 m. (b) Find ρ ν for r = 0.1m.(c) What
                                          surface charge density could be located at r = 0.08 m to cause D = 0 for
                                          r > 0.08 m?
                                     3.28 Repeat Problem 3.8, but use ∇ · D = ρ ν and take an appropriate volume
                                          integral.
                                     3.29 In the region of free space that includes the volume 2 < x, y, z < 3, D =
                                           2 2 (yz a x + xz a y − 2xy a z ) C/m .(a)Evaluate the volume integral side of
                                                                     2
                                           z
                                          the divergence theorem for the volume defined here. (b)Evaluate the surface
                                          integral side for the corresponding closed surface.
                                     3.30 (a) Use Maxwell’s first equation, ∇· D = ρ v ,to describe the variation of the
                                          electric field intensity with x in a region in which no charge density exists
                                          and in which a nonhomogeneous dielectric has a permittivity that increases
                                          exponentially with x. The field has an x component only; (b) repeat part (a),
                                          but with a radially directed electric field (spherical coordinates), in which
                                          again ρ v = 0, but in which the permittivity decreases exponentially with r.
                                                                 16            2
                                     3.31 Given the flux density D =  r  cos(2θ) a θ C/m , use two different methods to
                                          find the total charge within the region 1 < r < 2m,1 <θ < 2 rad,
                                          1 <φ < 2 rad.
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