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book   Mobk070    March 22, 2007  11:7








                                                                                                    165





                                                Appendix B



                   In this table q = (p/a) 1/2 ; a and x are positive real; α, β, γ are unrestricted; k is a finite integer;
                   n is a finite integer or zero; v is a fractional number; 1 · 2 · 3 ··· n = n!; 1 · 3 · 5 ··· (2n − 1) =
                                                                                          1
                   (2n − 1)!! n (n) =  (n + 1) = n!;  (1) = 0! = 1;  (v) (1 − v) = π/ sin vπ;  ( ) = π  1/2
                                                                                          2
                            NO.                 TRANSFORM                      FUNCTION
                                                      1
                            1                                                       1
                                                      p
                                                      1
                            2                                                       t
                                                     p 2
                                                      1                            t k−1
                            3
                                                     p k                          (k − 1)!
                                                      1                             1
                            4
                                                     p 1/2                        (πt) 1/2
                                                                                       1
                                                      1                             t  2
                            5                                                    2
                                                     p  3/2                         π
                                                      1                           2 k    k−1/2
                            6                                                           t
                                                    p k+1/2                  π 1/2 (2k − 1)!!
                                                      1                            t v−1
                            7
                                                     p v                            (v)
                                                                                     1
                            8                        p 1/2                      −
                                                                                      t
                                                                                  2π 1/2 5/2
                                                                                    3
                                                      3/2
                            9                        p
                                                                                     t
                                                                                 4π 1/2 5/2
                                                                                  k
                                                                               (−1) (2k − 1)!!
                            10                      p k−1/2
                                                                                 k
                                                                                     t
                                                                                2 π 1/2 k+1/2
                                                                                  t v−n−1
                            11                      p n−v
                                                                                  (v − n)
                                                      1
                            12                                                     e −α t
                                                    p + α
                                                      1                         e −β t  − e −α t
                            13
                                                (p + α)(p + β)                    α − β
                                                      1
                            14                                                    te −α t
                                                   (p + α) 2
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