Page 190 - Excel for Scientists and Engineers: Numerical Methods
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CHAPTER 8                ROOTS OF EQUATIONS                          I67



                   Examination  of  the  process  of  synthetic  division  reveals  that  there  is  a
               correspondence  between  the  coefficients  of  the  two  preceding  forms  of  the
               polynomial  :
                                                bn  = an                          (8-1 1)

                                            bn-1  = an-1 -pbn                     (8-12)

                                         bn-2  = ~  -  Fpbn-1 - qbn               (8-13)
                                                   2


                               bn-k = Un-k -pbn-k+l - qb,+k+2 (k = 2, 3, . . . , n-1)   (8-14)
                                           R = al -pb2  - qb3                     (8-15)

                                              S = a0  - qb2                       (8-16)
                   If the polynomial has been normalized so that an = 1, then the equations are
               simplified somewhat.
                   The trial quadratic will be a factor of the polynomial if the remainder is zero,
               that is, R = S = 0.  Since R and S are functions ofp and q:

                                                                                  (8-17)
                                               s = S@, 4)                         (8-18)

                we need to find the values of p  and q that make R and S equal to zero.  We will
                do this by  means of a two-dimensional analog of the Newton-Raphson method.
                If p*  and q*  are  the  desired  solution, then  the  solution can be  expressed  as a
                Taylor series


                                                                                  (8-19)

                and

                                                                                  (8-20)


                where                                                            (8-2 18)

                and                                                               (8-22)
                ignoring terms other that the first, since as we approach the correct answer the
                higher terms become negligible.  The preceding  result  in two equations  in  two
                unknowns, which can be solved to obtain
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