Page 64 - Fluid-Structure Interactions Slender Structure and Axial Flow (Volume 1)
P. 64

CONCEPTS, DEFINITIONS AND METHODS                    47

               For small motions, this reduces to
                                             a
                                             - v2+ = vv+.                          (2.144)
                                             at
               The boundary conditions match  the fluid velocity on  the  solid surfaces to those of  the
               two cylinders. In polar coordinates, u, = -(I/r)(a+/aO)  and ue  = a+/ar;  hence,

                                                                   =
                   uil   =a cos 8eia',   ~01 = -a  sin ,eia',  ~ ~ 1 %us1   = 0,   (2.145)
                      R,                   R,                           R"
               where a is the velocity amplitude of  the inner cylinder in the 8 = 0 plane.
                 This problem was solved by  Wambsganss et al. (1974) - see also Chen et a1. (1976).
               It may be verified that if
                                                v2+ = 0                           (2.146a)
               is satisfied, so is equation (2.144); similarly if
                                                   1 a+
                                              2
                                            v+---=o.                              (2.146b)
                                                   v  at
               Hence, a general solution in the form + =  + +2  is sought, with   and $2  satisfying
               (2.146a) and (2.146b), respectively. The form of  the boundary conditions suggests
                                $1  = Fl(r) sin dein',   $2  = F2(r) sin 8e'a',    (2.147)

               and hence FI and F2  must satisfy
                         d2FI   1  dF1   1
                         -++---F            I  =o,
                          dr2   r  dr   r2
                                                                                  (2.148)
                         d2F2   1 dF2             F2=0,
                         -+---
                         dr2    r  dr
               Each of these equations provides two independent solutions, hence four in total, as required
               and sufficient for the solution of equation (2.144), namely

                     9 = +I  + +2  = a[Alr-'  +A21 +A3Il(hr) +A4Kl(Ar)]  sin 8ein',   (2.149)
               in which the constants AI to A4  are determined via the boundary conditions. Once + is
               determined, the flow field is completely known and hence the stresses on the cylinders may
               be evaluated through equations (2.64) and (2.65). The force per unit length is given by
                               F = -p&a~[Rr(~) sin at + Sitir(H) COS at]           (2.150)

               (Chen et al. 1976), where

                      H  = {2a2[Io(a>Ko(B) - Io(B>Ko(a)l - 4a[Ii(a)Ko(B) + Io(B)Ki(a)l
                           + 'WIO(~)KI (B) + 11 (B)Ko(a)I - WI1 (a)Ki (B) - 11 (B)KI (a>l)
                           + (a2(1 - ~~>[b(a)Ko(B> Io(B)Ko(a)l + 2ay[Io(a)Ki(B)
                                                 -
                           - 11 (B)Ko(B) + 11 (B)Ko(a) - IO(B>KI (/%I+  2a~~[Io(B)Ki (a)
                           - b(a)KI (a> + 11 (a)Ko(B) - 11 (a)Ko(a)lI - 1.         (2.151)
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