Page 88 - Fundamentals of Communications Systems
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3.2   Chapter Three

                       Definition 3.1 Events A and B are mutually exclusive if A∩ B =∅
                       Axioms of Probability. A probability measure, P , for a probability space
                       ( , F, P ) with events A, B ∈ F must satisfy the following axioms

                       ■ For any event A, P (A) ≥ 0
                       ■ P ( ) = 1
                       ■ If A and B are mutually exclusive events then P (A∪ B) = P (A) + P (B).

                       These three axioms are the building blocks for probability theory and an
                       understanding of random events that characterize communication system
                       performance.



                       EXAMPLE 3.2
                       Example 3.1(cont.). The rolling of a fair die

                                       A 1 ={1}  A 2 ={2, 4, 6}  A 3 ={1, 2, 3}  A 4 ={1, 3, 5}
                                    P [{1}] = P [{2}] = ··· = P [{6}]                      (3.3)
                                           1          1          1         1
                                    P [A 1 ] =  P [A 2 ] =  P [A 3 ] =  P [A 4 ] =
                                           6          2          2         2


                                                                                C
                       Definition 3.2 (Complement) The complement of a set A, denoted A , is the set of all
                       elements of   that are not elements of A.

                       Theorem 3.1 Poincare For N events A 1 , A 2 , .....A N
                                     P [A 1 ∪ A 2 ∪ .... ∪ A N ] = S 1 − S 2 +· · ··+(−1) N −1  S N
                       where


                                    S k =        P [A i 1  ∩ A i 2  ∩ .... ∩ A i k ]  i 1 ≥ 1, i k ≤ N
                                        i 1 <i 2 <....<i k
                       Proof: The results are given for N = 2 and the proof for other cases is similar
                                                                        C
                       (if not more tedious). Note that events A and B ∩ A are mutually exclusive
                       events. Consequently we have
                                                        C
                                                                         C
                                    P [A∪ B] = P [(A∩ B ) ∪ B] = P [A∩ B ] + P [B]         (3.4)
                                                        C
                                                                         C
                                    P [A∪ B] = P [(B ∩ A ) ∪ A] = P [B ∩ A ] + P [A]       (3.5)
                                                                           C
                                                        C
                                    P [A∪ B] = P [(A∩ B ) ∪ (A∩ B) ∪ (B ∩ A )]
                                                                              C
                                                       C
                                             = P [A∩ B ] + P [A∩ B] + P [B ∩ A ]           (3.6)
                       Using Eq. (3.4) + Eq. (3.5) − Eq. (3.6) gives the desired result.
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