Page 104 - Fundamentals of Computational Geoscience Numerical Methods and Algorithms
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4.3  Application Examples of the Term Splitting Algorithm       91

                                                                      0.405E+02
                                                                      0.405E+02
                                                                      0.405E+02
                                                                      0.405E+02
                                                                      0.405E+02
                                                                      0.405E+02
                                                                      0.405E+02
                                                                      0.405E+02

                                (t = 3 × 10 9  s)


                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                               (t = 1.5 × 10 10  s)


                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                                                       0.405E+02
                                (t = 6 × 10 10  s)


                                                                       0.407E+02
                                                                       0.407E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02
                                                                       0.406E+02

                               (t = 1.5 × 10 11  s)
            Fig. 4.7 Distribution of quartz in the fluid-rock interaction system
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