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3.2  Mathematical Formulation of the Algorithm                  49

            (3) b 2  = 0, b 3  = 0

                                                 2
                                       −bb ±   bb − (4aa)cc
                                  η A =                    ,             (3.70)
                                               2aa
                                             c 2 − b 3 η A
                                        ξ A =        ,                   (3.71)
                                                b 2
            where
                                               a 4 b 3
                                          aa =     ,                     (3.72)
                                                b 2

                                          a 2 b 3 − a 4 c 2
                                     bb =           − b 3 ,              (3.73)
                                              b 2
                                              −a 2 c 2
                                         cc =      .                     (3.74)
                                                b 2


            3.2.2.4 Case 4: a 4  = 0, b 4  = 0
            In this case, Eqs. (3.37) and (3.38) can be written in the following form:

                                   ∗
                                         ∗
                                                      ∗
                                  a ξ A + a η A + ξ A η A = c ,          (3.75)
                                   2     3            1
                                                      ∗
                                  b ξ A + b η A + ξ A η A = c ,          (3.76)
                                   ∗
                                         ∗
                                   2     3            2
            where
                                 a i         b i
                             ∗           ∗
                            a =    ,    b =          (i = 2, 3),         (3.77)
                                         i
                             i
                                 a 4         b 4
                                       c 1           c 2
                                   ∗             ∗
                                  c =    ,      c =    .                 (3.78)
                                                 2
                                   1
                                       a 4           b 4
              Subtracting Eq. (3.78) from Eq. (3.77) yields the following equation:
                                    ∗
                                                       ∗
                                                ∗
                              (a − b )ξ A + (a − b )η A = c − c .        (3.79)
                               ∗
                                                           ∗
                                           ∗
                               2    2      3   3       1   2
              Clearly, if a − b = 0, the solutions to Eqs. (3.77) and (3.78) can be straightfor-
                        ∗
                            ∗
                        2
                            2
            wardly expressed as
                                            c − c ∗ 2
                                             ∗
                                             1
                                       η A =      ,                      (3.80)
                                             ∗
                                            a − b  ∗
                                             3   3
                                            ∗   ∗
                                           c − a η A
                                            1
                                                3
                                      ξ A =        .                     (3.81)
                                             ∗
                                            a + η A
                                             2
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