Page 165 - Fundamentals of Enhanced Oil and Gas Recovery
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153
             Thermal Recovery Processes

                                   1.0

                                   0.8                       a(t–t ) i   4a(t–t ) i
                                                      V :  θ =  r h 2  V :  θ =  h 1 2
                                                                    z
                                                        r
                                   0.6
                                 V                              V – (Single sand)
                                                                 z
                                   0.4
                                   0.2             V r
                                    0
                                     0.01      0.1       1.0       10        10C
                                                 θ  – Dimensionless time
                   Figure 5.4 Temperature time correlation.

                      The solution of the equation in r and z directions results in the following equa-
                   tions. This has been schematically represented in terms of dimensionless numbers in
                   Fig. 5.4.
                      r-direction for t D # 10
                                    r

                                      ffiffiffiffiffiffi
                                                    3       15       525
                                      t Dr    t Dr      2        3          4
                              T Dr 5      2 2    2    t Dr 2   t Dr 2    t Dr 2 .. .     (5.77)
                                      π       2    16       64       1024
                   for t D . 10

                                 1       1        5         1          7
                        T Dr 5      2        1         2        1            2 .. .      (5.78)
                                           2         3         4           5
                                4t Dr  16t Dr  384t Dr   439t Dr   20; 480t Dr
                      For z direction:
                                                          p
                                                            ffiffiffiffiffiffi
                                                   1        t Dz
                                       T Dz 5 erf p ffiffiffiffiffiffi 2    1 2 e 21=t Dz            (5.79)
                                                   t Dz     π
                      Two adjustments to Boberg Lantz made for this model include
                   1. T distribution in the o/u shale exists.
                         A hypothetical length (z) is added to the pay zone (h 1 z at T s ) to account for
                      heat loss to o/u.
                   2. The average temperature does not consider removal of heated fluids.
                      A dimensionless parameter (δ) is defined to adjust the temperature to account for
                   produced energy. Energy in a disk of radius r h and thickness z 1 h is calculated as
                   follows:

                                                    2
                                           m s H s 5 πr h MT s 2 T R Þðz 1 hÞ            (5.80)
                                                       ð
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