Page 106 - Fundamentals of Probability and Statistics for Engineers
P. 106

Expectations and Moments                                         89

             Proof of Property 4.2: to show Property 4.2, let t and u be any real quantities








           and form
                                                           2
                            …t; u†ˆ Ef‰t…X   m x †‡ u…Y   m Y †Š g
                                       2
                                                     2
                                 ˆ   20 t ‡ 2  11 tu ‡   02 u :
           Since  the expectation  of a  nonnegative function  of  X   and  Y  must  be non-

           negative,  (t, u)  is  a  nonnegative  quadratic  form  in  t  and  u,  and  we  must
           have
                                       20   02     2    0;               …4:25†
                                              11
           which gives the desired result.
             The normalization of the covariance through Equation (4.24) renders    a
           useful substitute for   11 . Furthermore, the correlation coefficient is dimension-
           less and independent of the origin, that is, for any constants a 1 , a 2 , b 1 , and b 2
           with a 1  > 0 and a 2  >  0, we can easily verify that
                               …a 1 X ‡ b 1 ; a 2 Y ‡ b 2 †ˆ  …X; Y†:   …4:26†

             Property 4.3. If X  and Y  are independent, then





                                     11 ˆ 0  and    ˆ 0:                 …4:27†








             Proof of Property 4.3: let X  and Y  be continuous; their joint moment   11 is
           found from
                                        Z  1  Z  1
                           11 ˆ EfXYgˆ          xyf  …x; y†dxdy:
                                                   XY
                                          1   1
           If X  and Y  are independent, we see from Equation (3.45) that
                                  f  …x; y†ˆ f …x†f …y†;
                                   XY        X    Y
           and
                       1   1                      1            1
                     Z   Z                      Z           Z
                  11 ˆ       xyf …x†f …y†dxdy ˆ     xf …x†dx    yf …y†dy
                                X    Y                X           Y
                       1   1                      1            1
                   ˆ m X m Y :
           Equations (4.23) and (4.24) then show that   11 ˆ 0 and   ˆ 0. A  similar result
           can be obtained for two independent discrete random variables.








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