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Some Important Continuous Distributions                         231

           the PDF of Z can be shown to have the form

                    F Z …z†ˆ 1 expf  exp‰ …z   u†Šg;  1 < z < 1         …7:105†


           where    and u are again the two parameters of the distribution.
             It is seen that Type-I asymptotic distributions for maximum and minimum
           values are mirror  images of each  other. The mode of Z  is u, and  its mean,
           variance, and skewness coefficients are, respectively,

                                              
   9
                                     m Z ˆ u      >
                                                  >
                                                  >
                                                  >
                                                  =
                                             2                          …7:106†
                                       2
                                       ˆ
                                       Z     2    >
                                          6       >
                                                  >
                                                  >
                                      
 1 ' 1:1396  ;
             For probability calculations, values for probability distribution functions
           F Y   (y) and F Z  (z) over various ranges of y and z are available in, for example,
           Microsoft Excel 2000 (see Appendix B).


             Example 7.9. Problem: the maximum daily gasoline demand  Y  during the


           month of May at a given locality follows the Type-I asymptotic maximum-
           value distribution, with m Y ˆ  2 and   Y   ˆ  1, measured in thousands of gallons.
           Determine  (a)  the  probability  that  the  demand  will  exceed  4000  gallons  in
           any day during the month of May, and (b) the daily supply level that for 95%
           of the time will not be exceeded by demand in any given day.
             Answer: it follows from Equations (7.102) and (7.103) that parameters    and
           u are determined from

                               ˆ p   ˆ p ˆ 1:282;
                                          
                                  6  Y    6
                                      0:577     0:577
                             u ˆ m Y       ˆ 2       ˆ 1:55:
                                                1:282
           For part (a), the solution is
                         P…Y > 4†ˆ 1   F Y …4†
                                 ˆ 1   expf exp‰ 1:282…4   1:55†Šg
                                 ˆ 1   0:958 ˆ 0:042:

           For part (b), we need to determine y such that

                                 F Y …y†ˆ P…Y   y†ˆ 0:95;








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