Page 240 - Fundamentals of Radar Signal Processing
P. 240

(4.32)

               It is a function of two variables: the time delay relative to the expected matched
               filter peak output, and the mismatch between that Doppler shift for which the
               filter was designed, and that which is actually received. For example, the AF
               evaluated at time t = 0 corresponds to the output of the actual matched filter at

               time t = 2R /c  + τ  for  a  target  at  range R . The particular form of the AF is
                              0
                                                                   0
               determined entirely by the complex waveform x(t).
                     Three properties of the ambiguity function are of immediate interest. The
               first states that if the waveform has energy E, then




                                                                                                       (4.33)

               Thus,  when  the  filter  is  matched  in  Doppler  to  the  echo  and  is  sampled  at  a
               delay corresponding to the target range, the response will be maximum. If the
               filter is not matched or is sampled at a different delay, then the response will be

               less  than  or  equal  to  (usually  less  than)  the  maximum.  The  second  property
               states that total area under any ambiguity function is constant and is given by




                                                                                                       (4.34)


               This conservation of energy statement implies that, in the design of waveforms,
               one  cannot  remove  energy  from  one  portion  of  the  ambiguity  surface  without
               placing  it  somewhere  else;  it  can  only  be  moved  around  on  the  ambiguity
               surface. The third property is a symmetry relation:




                                                                                                       (4.35)

                     In order to prove the first property, start with the square of Eq. (4.32)






                                                                                                       (4.36)

               Applying the Schwartz inequality to Eq. (4.36) yields









                                                                                                       (4.37)
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