Page 237 - Fundamentals of Radar Signal Processing
P. 237

(4.24)

               Thus, the matched filter for x′(t) can be obtained by simply shifting the center
               frequency of the matched filter for x(t) to the expected Doppler shift.

                     A  more  interesting  situation  occurs  when  the  velocity  is  not  known  in
               advance  so  that  the  receiver  filter  is  not  matched  to  the  target  Doppler  shift.
               More generally, suppose the filter is matched to some Doppler shift Ω  radians
                                                                                                    i
               per second but the actual Doppler shift of the echo is Ω . Choosing T  = 0 for
                                                                                                   M
                                                                                  D
               simplicity, the matched filter output will be zero for | t | > τ. For 0 ≤ t  ≤ τ the
               response is





                                                                                                       (4.25)

               If the filter is in fact matched to the actual Doppler shift, Ω  = Ω , the output
                                                                                               D
                                                                                        i
               becomes







                                                                                                       (4.26)

               The analysis is similar for negative t, –τ ≤ t ≤ 0. The complete result is







                                                                                                       (4.27)

               Thus, | y(t) | is the usual triangular function, peaking as expected at t = 0.
                     If there is a Doppler mismatch, Ω  ≠ Ω , the response at the expected peak
                                                                   D
                                                             i
               time t = 0 is













                                                                                                       (4.28)
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