Page 112 - Fundamentals of Reservoir Engineering
P. 112

PVT ANALYSIS FOR OIL                                   51



                                   Mass of 1 stb of oil              Mass of B o rb of oil
                                            +                =               +

                                  R s scf dissolved gas             dissolved gas in the
                                 at standard conditions                  reservoir

                                or

                                                lb                             lb
                                   1(stb) ρ×  o sc       ×  5.615 +   R (scf) ρ×  g sc

                                                                s
                                             	  cu.ft 
                     	  cu.ft
                                                            lb
                                                     ×
                                            =  B (rb) ρ r o       × 5.615
                                                o
                                                         	  cu.ft
                          in which the subscripts sc and r refer to standard conditions and reservoir
                          conditions, respectively.

                          The gas density at standard conditions is


                                ρ sc  = γ g × 0.0763 (refer equ. (1.30))

                                      = 0.0511 lb/cu ft

                          Therefore,

                                          (ρ o  × 5.615) (R ×  ρ g  )
                                                       +
                                                           s
                                 ρ      =   sc                 sc
                                  r o
                                                 B × 5.615
                                                  o
                                          (52.8 5.615) (352 0.0511)
                                                ×
                                                              ×
                                                        +
                                        =                               =  47.37 lb / cu ft
                                                 1.1822 5.615
                                                         ×
                          and the liquid oil gradient is 47.37/144 = 0.329 psi/ft.
              2.3    COLLECTION OF FLUID SAMPLES
                     Samples of the reservoir fluid are usually collected at an early stage in the reservoir's
                     producing life and dispatched to a laboratory for the full PVT analysis. There are
                     basically two ways of collecting such samples, either by direct subsurface sampling or
                     by surface recombination of the oil and gas phases. Whichever technique is used the
                     same basic problem exists, and that is, to ensure that the proportion of gas to oil in the
                     composite sample is the same as that existing in the reservoir. Thus, sampling a
                     reservoir under initial conditions, each stock tank barrel of oil in the sample should be
                     combined with R si standard cubic feet of gas.
                     a) Subsurface sampling


                     This is the more direct method of sampling and is illustrated schematically in fig. 2.6.
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