Page 129 - Fundamentals of Reservoir Engineering
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PVT ANALYSIS FOR OIL                                   68


                                    5.615 F           5.615 F     c    b
                           R   R   −          =  R  −               d
                            s =  si  f  c         si  f  c        c
                                         f b              b d         f b

                     which, using equ. (2.9), can be expressed as

                                                   B
                           R =  R si  − (R si  − R )    ob f                                        (2.12)
                                              s
                            s
                                         d
                                   f
                                              d
                                                   B ob
                                                     f

                     where
                     R si f  =   solution gas oil ratio of the bubble point oil, determined by flashing the oil
                     through the appropriate surface separators, and is measured relative to the oil volume
                     at 60°F and 14.7 psia (refer tables 2.3 and 2.4) (scf/stb).

                     R si  d  =   solution gas oil ratio of the bubble point oil determined during the

                                differential experiment and measured relative to the residual oil volume at
                                60°F and 14.7 psia (refer table 2.5 and equ. (2.10)) (scf/stb-residual).

                     The differential data, as presented in table 2.5, can be directly converted to the
                     required form, table 2.4, using the above relations. For instance, using the following
                     data from table 2.5, at a pressure of 2400 psi

                     B o d  =   1.2123  (rb /barrel of residual oil at 60°F and 14.7 psia)


                     R s  d  =     378 (scf/                —" —                      )

                     B ob  d  =  1.2830 (rb /               — " —                     )


                     R si d  =     540 (scf/                —" —                      )

                     while from the separator flash tests (table 2.3), for the optimum separator conditions of
                     150 psia and 80°F

                           B ob  f  = (1/ c ) 1.2511(rb / stb)
                                        =
                                      f b
                           R si  f  = 510 (scf / stb)


                     Therefore, using equ. (2.11)

                                         1.2511
                           B =   1.2123× 1.2830  =  1.1822 rb stb
                            o

                     and equ. (2.12)

                                                   1.2511
                           R =   510 (540 378)×            =  352 scf / stb
                                     −
                                           −
                            s
                                                   1.2830
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