Page 31 - Fundamentals of Reservoir Engineering
P. 31

CONTENTS                                      XXXI



                       k
                y k1  =  y − F k dF k                                                    (1.22)     19
                 +
                               dy
                                2
                                      3
                dF    1 4y +  4y −  4y +  y 4                  2  9.16t )y
                       +
                                                                       3
                                                       −
                dy  =        (1 y) 4         −  (29.52t 19.52t +
                               −
                                                                +
                                               2
                                                       3
                        +
                +  (2.18 2.82t) (90.7t −  242.2t +  42.4t )y  (1.18 2.82t)               (1.23)     19
                     V      p  T Z
               E =    sc  =    sc  sc                                                    (1.24)     21
                     V     p sc  T Z
                           p
               E =  35.37                   (vol/ vol)                                   (1.25)     21
                          ZT
                     φ
                G =  V (1 S )E i                                                         (1.26)     22
                        −
                           wc
                     nM        nM        Mp
                 ρ =      =           =                                                  (1.27)     22
                      V     ZnRT /p     ZRT
                ρ gas      M gas     M
                    =  γ =       =                                                       (1.28)     22
                       g
                ρ air      M air   28.97

               M =     nM i                                                              (1.29)     22
                        i
                      i
                            γ
                ρ =  0.0763 g (lbs / cu.ft)                                              (1.30)     22
                 sc
                        1 ∂  V    1      1 ∂ Z
                c =−            =    −                                                   (1.31)     23
                 g
                        V   ∂ p   p     Z ∂  p
                     1
                c =                                                                      (1.32)     23
                 g
                     p
                Production   =  GIIP −   Unproduced Gas
                   (sc)         (sc)          (sc)
                                                                                         (1.33)     25
                   G p       =  G     −   (HCPV)E
                                           G
                   G         =  G     −      E
                     p
                                          E i
                G p         E
                G   =  1 −  E i                                                          (1.34)     25


                p    p i       G                                                         (1.35)     25
                                 p
                Z  =  Z i     1 −  G

                                                                                         (1.36)     26
               d(HCPV) = − dV w +dV f
                         1   ∂ V      1   ∂ V
                                f
                c =−    V f  ∂ (FP)  =  f V  ∂ p f                                       (1.37)     26
                 f
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