Page 86 - Fundamentals of Reservoir Engineering
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SOME BASIC CONCEPTS IN RESERVOIR ENGINEERING                          25

                          To convert this number to a pressure gradient in psi/ft requires the following
                          manipulation.

                              dp             Ib     1        ft 2     6.696
                                    =  6.696   2  ×    ×       2    =       =  0.0465 psi/ ft.
                              dD   gas       ft     ft      inch      144


              1.7    GAS MATERIAL BALANCE: RECOVERY FACTOR


                     The material balance equation, for any hydrocarbon system, is simply a volume
                     balance which equates the total production to the difference between the initial volume
                     of hydrocarbons in the reservoir and the current volume. In gas reservoir engineering
                     the equation is very simple and will now be considered for the separate cases in which
                     there is no water influx into the reservoir and also when there is a significant degree of
                     influx.

                     a)   Volumetric depletion reservoirs

                     The term volumetric depletion, or simply depletion, applied to the performance of a
                     reservoir means that as the pressure declines, due to production, there is an
                     insignificant amount of water influx into the reservoir from the adjoining aquifer. This, in
                     turn, implies that the aquifer must be small (refer sec. 1.4). Thus the reservoir volume
                     occupied by hydrocarbons (HCPV) will not decrease during depletion. An expression
                     for the hydrocarbon pore volume can be obtained from equ. (1.26) as


                          HCPV = Vφ (1−S wc) = G/E i

                     where G is the initial gas in place expressed at standard conditions. The material
                     balance, also expressed at standard conditions, for a given volume of production G p,
                     and consequent drop in the average reservoir pressure ∆p = p i−p is then,

                           Production   =  GIIP −   Unproduced Gas
                              (sc)         (sc)          (sc)
                                                                                                    (1.33)
                              G p       =  G     −   (HCPV)E

                                                      G
                              G         =  G     −      E
                                p
                                                      E i
                     which can be expressed as

                           G p         E                                                            (1.34)
                           G   =  1 −  E i


                     or, using equ. (1.25), as

                           p    p         G
                                            p
                              =  i    1 −                                                           (1.35)
                           Z    Z i        G
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