Page 35 - Geochemistry of Oil Field Waters
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24                                        ANALYSIS OF OILFIELD WATERS


            TABLE 3.111
            Units in which water analyses may be reported
            milligrams per liter = mg/l         1 grain per U.S.  gallon = 17.12 mg/l

            part per million = ppm              1 grain per Imperial gallon = 14.3 mg/l
                    milligrams per liter        1 ppm = 0.012 milligram atom per liter
            ppm = specific gravity of  the water

            To convert compounds expressed as parts per million to ions expressed,as parts per
            million (where compound is A,  Bm):
                                            ,(atomic  weight A)
            ppm ion A  = ppm compound A,
                                       Bm  molecular weight A,  B,
                                            ,(atomic  weight B)
            ppm ion B = ppm compound A,
                                       Bm molecular weight A,  B,
            To convert parts per million to equivalents per million (epm):
              Example: sample contains 28.3 ppm Ca”  , what is the concentration of calcium in epm?
                      Solution; atomic weight Ca  = 40.08; valence = 2; equivalent weight =
                      40.08  = 20.04; then:
                        2
                            28 3
            28.3 ppm Ca+’  =  - = 1.41 epm Ca+’
                           20.04
            Titrim e tric analysis

                                     milliequivalent  weight   106
            (ml x  N of standard solution) x
                                       of determined  ion
                                      ml of  sample used    = mg/l of  determined  ion
            Gravimetric analysis

            (grams of preninitnta\ Y  ,.   atomic weight of determined element   106
                                  molecular
                                  ..._. -  weig
                      .,.F.’U”’,
                                             ,ht  of precipitate
                                                                      _.-
                                                                    ...
                               ml of sample used                   = me/l determined
                                                                         ~
                                                                    element
            %O  = parts per thousand or g/kg
            Chlorinity  (CZ)   = mass in grams of silver required  to precipitate the halogens in
                              328.5233 g of sea water
            Salinity (S)     = total amount of  solid material, in grams contained in 1 kg of
                              sea water when all of  the bromide and iodide have been replaced
                              by the equivalent amount of chloride, when all of the carbonate
                              is converted to oxide and when all the organic matter is completely
                              oxidized
            %o  S = 1.805 x  %o  Cl + 0.03
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