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4 . Solution with λ = λ 1,2 = λ ∗ and f 1 = f 2 = 0, where the characteristic value λ ∗ =
                      ◦
                           4
                                   is double:
                                 2
                             2
                     (A + B)(b – a )
                                                 y(x)= f(x)+ Cy ∗ (x),
                     where C is an arbitrary constant and y ∗ (x) is an eigenfunction of the equation corresponding
                     to λ ∗ :
                                                        (A – B)(b + a)
                                              y ∗ (x)= x –          .
                                                             4A

                              b
               4.    y(x) – λ  [A + B(x – t)]y(t) dt = f(x).
                             a
                     This is a special case of equation 4.9.8 with h(t)=1.
                        Solution:
                                              y(x)= f(x)+ λ(A 1 + A 2 x),

                     where A 1 and A 2 are the constants determined by the formulas presented in 4.9.8.

                              b
               5.    y(x) – λ  (Ax + Bt + C)y(t) dt = f(x).
                             a
                     This is a special case of equation 4.9.7 with g(x)= x and h(t)=1.
                        Solution:
                                              y(x)= f(x)+ λ(A 1 x + A 2 ),
                     where A 1 and A 2 are the constants determined by the formulas presented in 4.9.7.


                              b
               6.    y(x)+ A    |x – t| y(t) dt = f(x).
                              a
                     This is a special case of equation 4.9.36 with g(t)= A.
                      ◦
                     1 . The function y = y(x) obeys the following second-order linear nonhomogeneous ordinary
                     differential equation with constant coefficients:

                                                 y     +2Ay = f (x).                        (1)
                                                  xx
                                                             xx
                     The boundary conditions for (1) have the form (see 4.9.36)
                                             y (a)+ y (b)= f (a)+ f (b),




                                              x      x     x      x
                                                                                            (2)


                                    y(a)+ y(b)+(b – a)y (a)= f(a)+ f(b)+(b – a)f (a).
                                                     x                     x
                        Equation (1) under the boundary conditions (2) determines the solution of the original
                     integral equation.
                      ◦
                     2 .For A < 0, the general solution of equation (1) is given by
                                                             x                      √

                       y(x)= C 1 cosh(kx)+ C 2 sinh(kx)+ f(x)+ k  sinh[k(x – t)]f(t) dt,  k =  –2A,  (3)
                                                            a
                     where C 1 and C 2 are arbitrary constants.
                        For A > 0, the general solution of equation (1) is given by
                                                               x
                                                                                    √
                          y(x)= C 1 cos(kx)+ C 2 sin(kx)+ f(x)– k  sin[k(x – t)]f(t) dt,  k =  2A.  (4)
                                                             a
                        The constants C 1 and C 2 in solutions (3) and (4) are determined by conditions (2).

                 © 1998 by CRC Press LLC









               © 1998 by CRC Press LLC
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