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b
               13.   y(x) – λ  [g(x)g(t) – h(x)h(t)]y(t) dt = f(x).
                             a
                     The characteristic values of the equation:
                                                       2                           2
                                                  2
                                                                               2
                                   s 1 – s 3 +  (s 1 + s 3 ) – 4s  s 1 – s 3 –  (s 1 + s 3 ) – 4s
                              λ 1 =                    2  ,  λ 2 =                 2  ,
                                           2
                                                                        2
                                         2(s – s 1 s 3 )             2(s – s 1 s 3 )
                                           2                            2
                     where
                                      b                b                  b

                                        2
                                                                            2
                                s 1 =  g (x) dx,  s 2 =  g(x)h(x) dx,  s 3 =  h (x) dx.
                                     a                a                  a
                      ◦
                     1 . Solution with λ ≠ λ 1,2 :
                                           y(x)= f(x)+ λ[A 1 g(x)+ A 2 h(x)],
                     where the constants A 1 and A 2 are given by
                                     f 1 + λ(f 1 s 3 – f 2 s 2 )   –f 2 + λ(f 2 s 1 – f 1 s 2 )
                            A 1 =                       ,  A 2 =                      ,
                                          2
                                   2
                                                                 2
                                                                         2
                                 (s – s 1 s 3 )λ – (s 1 – s 3 )λ +1  (s – s 1 s 3 )λ – (s 1 – s 3 )λ +1
                                  2                              2
                                             b                   b

                                       f 1 =  f(x)g(x) dx,  f 2 =  f(x)h(x) dx.
                                            a                   a
                      ◦
                     2 . Solution with λ = λ 1 ≠ λ 2 and f 1 = f 2 =0:
                                                                     1 – λ 1 s 1
                                   y(x)= f(x)+ Cy 1 (x),  y 1 (x)= g(x)+    h(x),
                                                                       λ 1 s 2
                     where C is an arbitrary constant and y 1 (x) is an eigenfunction of the equation corresponding
                     to the characteristic value λ 1 .
                     3 . The solution with λ = λ 2 ≠ λ 1 and f 1 = f 2 = 0 is given by the formulas of item 2 in
                                                                                           ◦
                      ◦
                     which one must replace λ 1 and y 1 (x)by λ 2 and y 2 (x), respectively.
                                                                                           2
                     4 . Solution with λ = λ 1,2 = λ ∗ and f 1 = f 2 = 0, where the characteristic value λ ∗ =
                      ◦
                                                                                         s 1 – s 3
                     is double:
                                                                      s 1 + s 3
                                   y(x)= f(x)+ Cy ∗ (x),  y ∗ (x)= g(x) –  h(x),
                                                                       2s 2
                     where C is an arbitrary constant and y ∗ (x) is an eigenfunction of the equation corresponding
                     to λ ∗ .
                              b

               14.   y(x) – λ  [Ag(x)g(t)+ Bh(x)h(t)]y(t) dt = f(x).
                             a
                     The characteristic values of the equation:
                                                                          2
                                                                   2
                                            As 1 + Bs 3 ±  (As 1 – Bs 3 ) +4ABs
                                       λ 1,2 =                  2         2  ,
                                                      2AB(s 1 s 3 – s )
                                                                2
                     where
                                      b                b                  b

                                        2
                                                                            2
                                s 1 =  g (x) dx,  s 2 =  g(x)h(x) dx,  s 3 =  h (x) dx.
                                     a                a                  a
                      ◦
                     1 . Solution with λ ≠ λ 1,2 :
                                           y(x)= f(x)+ λ[A 1 g(x)+ A 2 h(x)],
                 © 1998 by CRC Press LLC









               © 1998 by CRC Press LLC
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