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where 0 < µ < 1. Let us assume that x ∈ [a, b], f(x) ∈ AC, and y(t) ∈ L 1 , and apply the technique
               of the fractional integration (see Section 8.5). We set
                                                                    ν
                                      µ =1 – β,    0 < β <1,   λ =     ,                   (19)
                                                                   Γ(β)
               and use (8.5.1) to rewrite Eq. (18) in the form
                                               β
                                          1 – νI  y(x)= f(x),   x > a.                     (20)
                                               a+
               Now the solution of the generalized Abel equation of the second kind can be symbolically written
               as follows:
                                                    β    –1
                                        y(x)= 1 – νI a+  f(x),  x > a.                     (21)
               On expanding the operator expression in the parentheses in a series in powers of the operator by
               means of the formula for a geometric progression, we obtain
                                                ∞       n

                                      y(x)= 1+      νI β     f(x),  x > a.                 (22)
                                                     a+
                                                n=1
                                           β  n  βn
               Taking into account the relation (I a+ ) = I a+ , we can rewrite formula (22) in the expanded form
                                           ∞     n     x
                                                ν           βn–1
                               y(x)= f(x)+             (x – t)  f(t) dt,  x > a.           (23)
                                              Γ(βn)  a
                                           n=1
               Let us transpose the integration and summation in the expression (23). Note that
                                       ∞   n     βn–1      ∞   n     βn
                                          ν (x – t)     d     ν (x – t)
                                                     =                 .
                                            Γ(βn)      dx     Γ(1 + βn)
                                      n=1                 n=1
               In this case, taking into account the change of variables (19), we see that a solution of the generalized
               Abel equation of the second kind becomes
                                                   x
                                     y(x)= f(x)+   R(x – t)f(t) dt,  x > a,                (24)
                                                 a
               where the resolvent R(x – t) is given by the formula
                                                  ∞
                                               d       λΓ(1 – µ)(x – t) (1–µ) 	 n
                                     R(x – t)=                          .                  (25)
                                              dx        Γ[1 + (1 – µ)n]
                                                 n=1
               In some cases, the sum of the series in the representation (25) of the resolvent can be found, and a
               closed-form expression for this sum can be obtained.
                   Example 2. Consider the Abel equation of the second kind (we set µ =  1  in Eq. (18))
                                                                 2
                                                x  y(t)

                                         y(x) – λ  √   dt = f(x),  x > a.                  (26)
                                               a   x – t
               By virtue of formula (25), the resolvent for Eq. (26) is given by the expression
                                                          √     	 n
                                                     ∞
                                                   d    λ π(x – t)
                                           R(x – t)=               .                       (27)
                                                  dx     Γ 1+  1  n
                                                     n=1      2
               We have
                                    ∞    n/2                          x
                                        x        x  √           2     –t 2
                                               = e erf  x,  erf x ≡ √  e  dt,              (28)
                                      Γ 1+  1  n                 π

                                    n=1    2                        0
               where erf x is the error function. By (27) and (28), in this case the expression for the resolvent can be rewritten in the form
                                              d
                                                    2
                                      R(x – t)=  exp[λ π(x – t)] erf λ  π(x – t)  .        (29)
                                             dx
               Applying relations (24) and (27), we obtain the solution of the Abel integral equation of the second kind in the form
                                       d     x
                                                 2
                             y(x)= f(x)+     exp[λ π(x – t)] erf λ  π(x – t)  f(t) dt,  x > a.  (30)
                                       dx  a
               Note that in the case under consideration, the solution is constructed in the closed form.
                 © 1998 by CRC Press LLC







               © 1998 by CRC Press LLC
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