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9.5-4. Generating Function Containing Sines and Cosines
               Consider the linear equation
                                                L [y] = sin(λx).                           (11)
               We assume that the solution of this equation is known and is given by formula (2).  In Table 6,
               solutions of the equation L [y]= f(x) with various right-hand sides are given, which are expressed
               via the solution of Eq. (11).
                   Consider the linear equation
                                                L [y] = cos(λx).                           (12)
               We assume that the solution of this equation is known and is given by formula (2).  In Table 7,
               solutions of the equation L [y]= f(x) with various right-hand sides are given, which are expressed
               via the solution of Eq. (12).
                                                   TABLE 6
                        Solutions of the equation L [y]= f(x) with sine-shaped generating function
                No Right-Hand Side f(x)          Solution y               Solution Method

                 1        sin(λx)                  y(x, λ)                Original Equation

                 2      n    A k sin(λ k x)     n    A k y(x, λ k )     Follows from linearity
                       k=1                      k=1
                              m                m–1     m
                           Ax ,                     ∂                  Follows from the results
                 3                        A(–1)  2      y(x, λ)
                       m = 1,3,5, ...               ∂λ m       λ=0        of row 5 for λ =0
                           m                      m ∂ m
                        Ax sin(λx),                                        Differentiation
                 4                           A(–1) 2    y(x, λ)
                       m = 2,4,6, ...               ∂λ m             with respect to the parameter λ
                          m
                        Ax cos(λx),              m–1 ∂ m              Differentiation with respect
                 5                          A(–1)  2     y(x, λ)
                       m = 1,3,5, ...                ∂λ m                 to the parameter λ
                                                                       Relation to the hyperbolic
                 6        sinh(βx)               –iy(x, iβ)
                                                                            sine, λ = iβ
                         m
                        x sinh(βx),           m+2     ∂ m             Differentiation with respect
                 7                        i(–1)  2     y(x, λ)          to λ and relation to the
                       m = 2,4,6, ...              ∂λ m       λ=iβ      hyperbolic sine, λ = iβ
                                                   TABLE 7
                       Solutions of the equation L [y]= f(x) with cosine-shaped generating function
                No Right-Hand Side f(x)          Solution y               Solution Method
                 1        cos(λx)                  y(x, λ)                Original Equation

                 2      n    A k cos(λ k x)     n    A k y(x, λ k )     Follows from linearity
                       k=1                      k=1
                              m
                           Ax ,                 m     ∂ m              Follows from the results
                 3                         A(–1) 2     y(x, λ)
                       m = 0,2,4, ...              ∂λ m       λ=0         of row 4 for λ =0
                          m
                        Ax cos(λx),               m ∂ m                    Differentiation
                 4                           A(–1) 2    y(x, λ)
                       m = 2,4,6, ...               ∂λ m             with respect to the parameter λ
                           m
                        Ax sin(λx),              m+1 ∂ m                   Differentiation
                 5                          A(–1)  2     y(x, λ)
                       m = 1,3,5, ...                ∂λ m            with respect to the parameter λ
                                                                       Relation to the hyperbolic
                 6        cosh(βx)                y(x, iβ)
                                                                           cosine, λ = iβ
                         m
                        x cosh(βx),            m     ∂ m              Differentiation with respect
                 7                         (–1) 2     y(x, λ)           to λ and relation to the
                       m = 2,4,6, ...             ∂λ m       λ=iβ      hyperbolic cosine, λ = iβ

                 © 1998 by CRC Press LLC









               © 1998 by CRC Press LLC
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