Page 77 - Handbook Of Multiphase Flow Assurance
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72                             4.  Hydraulic and thermal analysis

                   If the Reynolds number is below 2100, the laminar Moody friction factor as a function of
                 Reynolds number is
                                                  f Moody  = 64/Re
                                                  f Fanning  =  f Moody / 4
                   Many different friction factor correlations are available for turbulent flow but the simplest
                 of these is the Blasius (1913) correlation.

                                                               .
                                               f    = 0 3164Re −025
                                                       .
                                                Moody
                   For turbulent flow it is convenient to determine friction factor f from a non-recursive for-
                 mula (Swamee and Jain, 1976)
                                                                               −2
                                  f Fanning  =  f Moody  /4  = ( 4 ×log ( /.37ε  (  D) + .574 /Re  . 09 )) .
                                                                                            −6
                   ε = pipe wall roughness [m]; typical aged carbon steel roughness is 45 μm or 45 × 10  m. Re
                 is Reynolds number.
                   For hydraulically smooth pipes f Fanning  = 0.0791/Re 0.25 .
                   For flow analysis it is helpful to estimate shear of fluid acting either on a solid or on pipe
                 wall. We summarize several shear correlations.

                            [
                                                                            (
                                                Pa /
                  Shear_rateγ 1/ s] = shear_stressτ [ ]  dynamic_viscosity µ[ Pas] ffor Newtonian fluids).
                   Shear rate for laminar flow γ Laminar  = 8 v Ave /D.
                   Average flow velocity v Ave  = Q/A.
                   Shear stress exerted by flowing fluid on pipe wall τ wall  = D ΔP/(4L)


                                        τ          = 8µ V  /  D
                                         Laminaratwall  Ave
                                             __
                                        τ          = ρ Vf     /2
                                                        2
                                              __
                                         Turbulentatwall  Fanning
                                        τ   = DP (   L)
                                               ∆ /4
                                         w wall
                   For single-phase flow we can illustrate that laminar pressure drop is inversely propor-
                 tional to pipe diameter to the power 4, whereas turbulent flow is inversely proportional to
                 diameter to the power 5.
                                                                          4
                                                         2
                                                                    /
                                    ∆P Laminar  = 32µ Lv Ave  /  D ( ) = 128 µ LQ (π D )
                                                                        2
                                                                                5
                                              L v
                                                          / 2
                                    ∆P Turbulent  = 4 ρ  Ave 2 f Faanning (  D) = 32ρ LQf /(π 2 D )
                   Other equations such as Weymouth or Panhandle may also be used to calculate pressure
                 drop in gas flow. Panhandle B formula (1956) is for gas flow with medium Reynolds number
                 values.
                                                              P − )
                                     [
                                            /
                                                          . 253
                                   Q MMscf d] = 0  .028 ED ( ( 1 2  P 2 2  /( S  . 0 961  ZTL))  . 051
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