Page 251 - Handbook of Energy Engineering Calculations

(315.6°C) for saturated liquid.

6. Compute the pressure loss through the fluidized bed
Use the relation p = 2.9 h[(l − P) d + Pd ], where p = pressure loss through
f
w
3
2
fluidized fuel bed, lb/ft ; d = fuel density, lbm/ft ; other symbols as before.
f
2
Substituting, we find p = 2.9 [(1 − 0.4)700 + 0.4 × 42.45] = 1268 lb/ft or
2
8.79 lb/in (60.6 kPa).
Related Calculations. This general procedure is valid for preliminary
selection of the type of nuclear reactor to use for a given power application.
Since reactors are expensive, a complete economic analysis must be made of

the alternatives available before the final choice is made.

ANALYSIS OF NUCLEAR POWER-PLANT CYCLES

A nuclear power plant using two coolants, Na and NaK, is arranged as shown
in Fig. 1. Sodium, the first coolant, enters the reactor at 600°F (315.6°C) and
leaves at 1000°F (537.8°C); NaK, the second coolant, enters the intermediate
heat exchanger at 550°F (287.8°C) and leaves at 950°F (510.0°C). Neglecting

heat and pressure losses in the piping, plot the enthalpy-temperature diagram
2
for the plant if steam leaves the boiler at 1200 lb/in (8273 kPa). What are the
Na and NaK flow rates with the cycle arrangement shown in Fig. 1, a reactor

capacity of 400,000 kW of heat energy, and a 155,000-kW turbine output?
Determine the plant thermal efficiency if the auxiliary-power needs = 12,000
kW.