Page 352 - Handbook of Energy Engineering Calculations
P. 352

As a rule of thumb for thermal-storage wall systems, provide a minimum
                       3
                                   3
               of 1 ft  (0.30 m ) of dark-colored thermal storage material per square foot
                                                                                   3
                                                                        3
               (meter) of collector for masonry walls or 0.5 ft  (0.15 m ) of water per square
               foot (meter) of collector for a water wall. This will provide enough thermal
               storage material to maintain the inside space temperature fluctuation within

               15°F (8.33°C).


               6. Determine the surface area of storage material for a direct-gain space
               In a direct-gain system, the insolation must be spread over the surface area of
               the storage material to prevent overheating. Generally, the larger the surface
               area of material, the lower the inside temperature fluctuation, and thus the

               space is more comfortable. To determine this area, enter Fig. 15 at the lower
               axis to select an acceptable space temperature fluctuation. Project vertically
               to  the  curve,  and  read  left  to  the  A /A   ratio.  This  is  the  ratio  of  thermal
                                                            S
                                                                C
               storage  material  surface  to  collector  area,  where  A   =  surface  of  storage
                                                                                S
                                                                                           2
                                                                                                2
               material  receiving  direct,  diffused  or  reflected  insolation,  ft   (m ).  In  this
               example, 15°F (8.33°C) is selected, requiring A /A  = 6.8. Thus, A  = (6.8)
                                                                          S
                                                                              C
                                                                                                  S
                                          2
                               2
               (42) = 286 ft  (26.5 m ).
                  This step is not required for the design of thermal-storage wall systems in
               which A  = A .
                         S
                               C
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