Page 49 - Handbook of Energy Engineering Calculations
P. 49

4, times the proportion of N  in the air, or 0.79. The excess O  passes through
                                                                                         2
                                                 2
               the furnace and adds to the combustion products and is computed as shown in
               the  tabulation.  Subtracting  the  total  moisture,  3430  mol,  from  the  total  (or

               wet) combustion products gives the moles of dry combustion products.


               Related Calculations. Use this method for molal combustion calculations for
               all types of fuels—solid, liquid, and gaseous—burned in any type of furnace
               —boiler, heater, process, or waste-heat. Select the correct factors from Table

               3.


               ESTIMATING  THE  TEMPERATURE  OF  THE  FINAL
               PRODUCTS OF COMBUSTION




               Pure carbon is burned to carbon dioxide at constant pressure in an insulated
               chamber. An excess air quantity of 20 percent is used and the carbon and the
               air  are  both  initially  at  77°F  (25°C).  Assume  that  the  reaction  goes  to

               completion  and  that  there  is  no  dissociation.  Calculate  the  final  product’s
               temperature using the following constants: Heating value of carbon, 14,087
                                         3
               Btu/lb  (32.74  ×  10   kJ/kg);  constant-pressure  specific  heat  of  oxygen,
               nitrogen, and carbon dioxide are 0.240 Btu/lb  (0.558 kJ/kg), 0.285 Btu/lb                  m
                                                                       m
               (0.662 kJ/kg), and 0.300 Btu/lb (0.697 kJ/kg), respectively.


               Calculation Procedure:



               1.  Establish  the  chemical  equation  for  complete  combustion  with  100
                  percent air
               With 100 percent air: C + O  + 3.78N  → CO  + 3.78N , where approximate
                                                 2
                                                                                   2
                                                                       2
                                                             2
               molecular weights are: for carbon, MC = 12; oxygen, MO  = 32; nitrogen,
                                                                                        2
               MN  = 28; carbon dioxide, MCO  = 44. See the Related Calculations of this
                    2
                                                        2
               procedure for a general description of the 3.78 coefficient for N .
                                                                                            2
               2. Establish the chemical equation for complete combustion with 20 percent

                  excess air
               With 20 percent excess air: C + 1.2O  + (1.2 × 3.78)N  → CO  + 0.2O  +
                                                                                              2
                                                                                                         2
                                                                                    2
                                                              2
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