Page 82 - Handbook of Energy Engineering Calculations
P. 82

the proposed binary cycle. Find the cycle efficiency without mercury.


               Calculation Procedure:


               1. Tabulate the key enthalpies and entropies for the cycle
               Set up two columns, thus:















               2. Compute the quality of the exhaust for each vapor
               Since expansion in each turbine is at constant entropy, Fig. 14b, the quality
               for the mercury exhaust, x  is: 0.1194 = 0.0299 + x (0.1l21); x  = 0.798.
                                                                                           m
                                               m
                                                                             m
                  For the steam cycle, the quality, x  is: 1.6293 = 0.1326 + x (1.8456); x  =
                                                                                           s
                                                                                                         s
                                                            s
               0.81.
               3. Find the exhaust enthalpy for each vapor
               Using  the  properties  of  mercury  from  a  set  of  tables,  the  enthalpy  of  the
               mercury exhaust, H  = 22.6 + 0.798(123) = 120.7 Btu/lb (281.2 kJ/kg). The
                                       me
               enthalpy of the condensed mercury, H  = 22.6 Btu/lb (52.7 kJ/kg).
                                                             mf
                  For  the  exhaust  steam,  the  enthalpy  H   =  69.7  +  0.81(1036.3)  =  909.1
                                                                   se
               Btu/lb (2118 kJ/kg), using steam-table data. The enthalpy of the condensed
               steam, H  = 69.7 Btu/lb (162.4 kJ/kg).
                          sf
                  Assuming 98 percent quality steam leaving the mercury condenser, then
               the enthalpy of the wet steam leaving the mercury condenser, H  = 571.7 +
                                                                                              sw
               0.98(611.7) = 1171.2 Btu/lb (2728 kJ/kg).
   77   78   79   80   81   82   83   84   85   86   87