Page 83 - Handbook of Energy Engineering Calculations
P. 83
FIGURE 14 (a) Binary cycle. (b) T-S diagram for binary cycle.
4. Write the heat balance around the mercury condenser
The steam heat gain = H − H = 1171.2 − 69.7 = 1101.5 Btu/lb (2566.5
sw
sf
kJ/kg). Now, the mercury heat loss = H − H = 120.7 − 98.1 = 98.1 Btu/lb
me
mf
(228.6 kJ/kg). The weight of mercury per pound (kg) of steam = steam heat
gain/mercury heat loss = 1101.5/98.1 = 11.23.
5. Determine the heat input and work done per pound (kg) of steam
The heat input per pound of steam is: For mercury = (lb Hg/lb steam)(H −
m1
H ) = 11.23(151.1 − 22.6) = 1443.05 Btu (1522.5 J). For steam = (H −
mf
s1
H ) = 1499.2 − 1171.7 = 327.5 Btu (345.5 J). Summing these two results
sw
