Page 178 - Handbook of Structural Steel Connection Design and Details
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Design of Connections for Axial, Moment, and Shear Forces

                           Design of Connections for Axial, Moment, and Shear Forces  163
























                    Figure 2.62 A shear connection needing reinforcement to carry axial load of
                    39 kips.
                    and
                                                   t  2
                                           T d 5  r t a b s1 1  r  d
                                                   t c
                      All other equations remain the same.
                      As an example of the application of this method, consider the connection
                    of Fig. 2.62. Assume this was designed originally for a shear of 60 kips, but
                    now must carry an axial force of 39 kips when the shear is at 33 kips. Let
                    us check the axial capacity of this connection. The most critical limit state
                    is prying action because of the thin angle leg thickness. From Fig. 2.62
                                           5.5 2 0.355 2 0.25
                                       b 5                    5 2.45
                                                   2
                                           8 1 0.355 2 5.5
                                       a 5                 5 1.43
                                                  2
                                       1.25   2.45   3.06 > 1.43

                      Use a   1.43. Then b   2.08, a   1.81,    1.15,     0.72, V   33/8
                    4.125 kips/bolt. The holes are HSSL (horizontal short slots), so  r   9.41
                                                                              v
                    kips/bolt. Since 4.125   9.41, the bolts are ok for shear (as they obviously
                    must be since the connection was originally designed for 60 kips shear).
                    Because this is a shear connection, the shear capacity is reduced by the
                    tension load by the factor 1-T/(1.13T ), where T is the applied load per
                                                      b
                    bolt and T is the specified pretension.
                              b
                      Thus, the reduced shear design strength is
                                                          T
                                               5  r a1 2
                                           r v    v           b
                                                        1.13T b



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