Page 110 - How To Solve Word Problems In Calculus
P. 110
Substituting into the equation for S obtained in step 2, we
obtain S as a function of r.
2000
S(r) = 2πr + 2πr 2
πr 2
4000
S(r) = + 2πr 2 0 < r < ∞
r
Step4
S(r) = 4000r −1 + 2πr 2
S (r) =−4000r −2 + 4πr
4000
0 =− + 4πr
r 2
4000
= 4πr
r 2
3
4πr = 4000
1000
3
r =
π
10
r = √ in
3 π
2000
Since h = , the corresponding height is
πr 2
2000 2000 2000 20
h = = = = √ in
2 100 1/3 3
10 100π π
π √ π 2/3
3 π π
Step5
S (r) = 8000r −3 + 4π
8000
= + 4π
r 3
97