Page 105 - How To Solve Word Problems In Calculus
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1   3
                                       x = 0     t(0) =   +
                                                        3   5
                                                        14
                                                     =     h (56 minutes)
                                                        15

                                                              2
                                                           3
                                                                + 1        3
                                                                      3 −
                                         3        3        4               4
                                     x =       t     =              +
                                         4        4          3           5

                                                          9         9    5    9
                                                             + 1
                                                          16        4    4    4
                                                     =           +    =    +
                                                            3       5    3    5
                                                        5     9    208
                                                     =     +     =
                                                        12   20    240
                                                        13
                                                     =     h (52 minutes)
                                                        15
                                                        √
                                                          10
                                       x = 3     t(3) =      ≈ 1.054 h (63.2 minutes)
                                                         3
                                                                             13
                                   The minimum time to go from A to B is        h.
                                                                             15
                               EXAMPLE 10

                               What is the largest possible volume a right circular cylinder
                               can have if it is inscribed in a sphere of radius 5?

                                   Solution
                                   Step1
                                   We examine the figure geometrically from a two-
                               dimensional perspective.


                                                               r
                                                            h
                                                            2   5
                                                      h








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