Page 122 - How To Solve Word Problems In Calculus
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40y − 2xy = 400 − 40x

                                                        20y − xy = 200 − 20x
                                    Finally we factor y from each term on the left and divide by its
                                    coefficient.
                                                       (20 − x)y = 200 − 20x

                                                                  200 − 20x
                                                              y =
                                                                    20 − x
                                    The smallest allowable value of x, leading to a degenerate triangle, is
                                    x = 0; the largest value occurs when y = 0. Since

                                                   2
                                               2
                                    x + y +  x + y = 20, when y = 0, 2x = 20 or x = 10. Hence
                                    0 ≤ x ≤ 10.
                                         To compute the critical values, we first express the area in
                                    terms of x.
                                                             1
                                                         A =  xy
                                                             2

                                                             1   200 − 20x
                                                           =  x
                                                             2     20 − x
                                                             100x − 10x 2
                                                      A(x) =
                                                                20 − x
                                    The derivative is calculated using the quotient rule. Once obtained,
                                    we set it to 0.
                                                                                 2
                                                  (20 − x)(100 − 20x) − (100x − 10x )(−1)

                                           A (x) =
                                                                 (20 − x) 2
                                                                   2
                                                  2000 − 500x + 20x + 100x − 10x 2
                                                =
                                                              (20 − x) 2
                                                      2
                                                  10x − 400x + 2000
                                                =
                                                       (20 − x) 2
                                                      2
                                                  10x − 400x + 2000
                                              0 =
                                                       (20 − x) 2
                                                     2
                                              0 = 10x − 400x + 2000
                                                   2
                                              0 = x − 40x + 200
                                                                                √
                                                                                   2
                                                                           −b ±   b − 4ac
                                    To find x, we use the quadratic formula: x =           .
                                                                                 2a
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