Page 112 - Instant notes
P. 112

Physical chemistry     98


        substance whose molecular mass is unknown. Addition of a given mass of this substance
        as B to a solvent to form an ideal-dilute solution allows the determination of a colligative
        property to obtain  x B,  molality  m B or  concentration  c B. Using the number of moles,
        volume or mass of the solvent (all of which are related) respectively then enables the
        determination of the number of moles of B added. This, in conjunction with the added
        mass of B, allows the molar mass (or mass of one mole) of B to be determined.


                             Depression of solvent freezing point

        For the equilibrium corresponding to the physical  transition  of A between solid and
        liquid:


        the activity of the solvent A in the liquid is given by a A=x A (see Topic D1). This means
        that the small amount of the solute, B, added in an ideal-dilute solution  affects  this
        activity. Equilibrium is established only at the freezing temperature or freezing point
        (which is the same as the melting temperature or melting point) of A. Below this
        temperature, all of the liquid A has frozen and A is only present as  solid;  above  this
        temperature, all the solid A has melted and only liquid A is present. At the equilibrium
        temperature, the change in Gibbs free energy and hence the equilibrium constant, K, for
        the reaction is dominated by A (as there is a minute amount of B present) and is given by
        K=x A, as pure solid A has an activity of 1 (see Topic C1).
           The temperature variation of this equilibrium  constant  is  given  by  the  van’t Hoff
        equation (see Topic C1):




        where      is the standard enthalpy of fusion (the enthalpy required to melt a mole of
        solid A under standard  conditions). For pure liquid A,  K T2=x A=1 and   , the
        freezing point of pure liquid A, whereas when B is added, K T1=x A and T 1=T f, the new
        freezing point. Therefore:





        which gives
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