Page 217 - Solutions Manual to accompany Electric Machinery Fundamentals

The speed is given by
E 12 V
  A   262 rad/s

 K 7.64 0.006 Wb 

n  m  262 rad/s   1 r     60 s    2500 r/min
 2 rad    1 min 

(b) If the positive terminal of the battery is connected to the rightmost brush, current will flow into the
page under the South pole face, producing a CW torque  CW rotation.
(c) If the motor consumes 600 W from the battery, the current flow is
P 600 W
I    50 A
V B 12 V

Therefore, the induced torque will be

 ind  KI   A 7.64 0.006 Wb 50 A  2.29 N m, CW 
7-9. Refer to the machine winding shown in Figure P7-3.

211