Page 227 - Solutions Manual to accompany Electric Machinery Fundamentals
P. 227

From Figure P8-1, this field current would produce an internal generated voltage  E  of 271 V at a speed
                                                                                           Ao
                  n   of 1200 r/min.  At no-load conditions, the minimum internal generated voltage  E   V  = 120 V.
                   o                                                                            A    A
                 Therefore, the speed n with a voltage of 120 V would be
                         E A    n
                         E Ao  n o
                              E        120 V 
                         n     A    n o        1200  r/min     531 r/min
                              E Ao     271 V 
          For Problems 8-10 to 8-11, the motor is connected cumulatively compounded as shown in Figure P8-4.






















          8-10.  If the motor is connected cumulatively compounded with  R adj  = 175 :

                     (a)  What is the no-load speed of the motor?
                     (b)  What is the full-load speed of the motor?
                     (c)  What is its speed regulation?

                     (d)  Calculate and plot the torque-speed characteristic for this motor.  (Neglect armature effects in this
                     problem.)

                 SOLUTION  At no-load conditions,  E  V   240 V .  The field current is given by
                                                     T
                                                 A
                                V          240 V      240 V
                         I      T                          0.960 A
                             R   F  adj  R F  175     75   250 

                 From Figure P8-1, this field current would produce an internal generated voltage  E  of 241 V at a speed
                                                                                           Ao
                  n o  of 1200 r/min.  Therefore, the speed n with a voltage of 240 V would be
                         E A    n
                         E Ao  n o
                              E        240 V 
                         n     A     n o           1200 r/min   1195 r/min
                              E Ao     241 V 

                 At full load conditions, the armature current is
                                            V
                                                          
                         I   A  I   L  I   F  I   L  R  R F    110 A   0.96 A     109 A
                                             T
                                           adj
                 The internal generated voltage  E  is
                                               A
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