Page 149 - Intro to Tensor Calculus
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               is now demonstrated. By using the results from equation (1.5.50), the tensor derivative of equation (1.5.59),
               with respect to the surface coordinates, produces

                                                    2 i
                                                   ∂ x        i     p  q     σ     i
                                            i
                                           x   =         +       x x −          x                     (1.5.68)
                                            α,β     α  β           α β           σ
                                                 ∂u ∂u      pq            αβ
                                                                g              a
               where the subscripts on the Christoffel symbols refer to the metric from which they are calculated. Also the
               tensor derivative of the equation (1.5.57) produces the result
                                                      j
                                                             i
                                               g ij x i  x + g ij x x j  = a αβ,γ =0.                 (1.5.69)
                                                   α,γ β     α β,γ
               Interchanging the indices α, β, γ cyclically in the equation (1.5.69) one can verify that


                                                        g ij x i α,β γ j                              (1.5.70)
                                                              x =0.
               The equation (1.5.70) indicates that in terms of the space coordinates, the vector x i  is perpendicular to
                                                                                         α,β
                                        i
                                                                                                  i
               the surface tangent vector x and so must have the same direction as the unit surface normal n . Therefore,
                                        γ
               there must exist a second order tensor b αβ such that
                                                            i
                                                        b αβ n = x i α,β .                            (1.5.71)

                                      i j
               By using the relation g ij n n = 1 we can transform equation (1.5.71) to the form
                                                               1  γδ   i   j  k
                                                       j i
                                              b αβ = g ij n x  =      ijk x  x x .                    (1.5.72)
                                                         α,β           α,β γ δ
                                                               2
               The second order symmetric tensor b αβ is called the curvature tensor and the quadratic form
                                                                 α
                                                       B = b αβ du du β                               (1.5.73)

               is called the second fundamental form of the surface.
                   Consider also the tensor derivative with respect to the surface coordinates of the unit normal vector to
               the surface. This derivative is
                                                         ∂n i    i    j k
                                                    i
                                                  n ,α  =   +        n x .                            (1.5.74)
                                                                        α
                                                        ∂u α    jk
                                                                    g
                                                i j
               Taking the tensor derivative of g ij n n = 1 with respect to the surface coordinates produces the result
                                                                         i
                   i j
               g ij n n  = 0 which shows that the vector n j  is perpendicular to n and must lie in the tangent plane to the
                     ,α                              ,α
                                                                                                 i
               surface. It can therefore be expressed as a linear combination of the surface tangent vectors x and written
                                                                                                 α
               in the form
                                                                β i
                                                         n i  = η x                                   (1.5.75)
                                                           ,α   α β
                                    β
               where the coefficients η can be written in terms of the surface metric components a αβ and the curvature
                                    α
                                                       i
               components b αβ as follows. The unit vector n is normal to the surface so that
                                                            i j
                                                         g ij n x =0.                                 (1.5.76)
                                                              α
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