Page 144 - Intro to Tensor Calculus
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139



               where J is the Jacobian of the surface coordinate transformation. Here the curvature tensor for the surface
               R αβγδ has only one independent component since R 1212 = R 2121 = −R 1221 = −R 2112 (See exercises 20,21).
               From the transformation law
                                                                       γ
                                                                α
                                                                   β
                                                             ∂u ∂u ∂u ∂u   δ
                                                ¯
                                                R  ηλµ = R αβγδ     η  λ   µ
                                                             ∂¯u ∂¯u ∂¯u ∂¯u
                                                                            2
                                                               ¯
               one can sum over the repeated indices and show that R 1212 = R 1212 J and consequently
                                                      ¯
                                                      R 1212  R 1212
                                                           =       = K
                                                        ¯ a    a
               which shows that the Gaussian curvature is a scalar invariant in V 2 .
               Geodesic Curvature

                                                                                ~
                   For C an arbitrary curve on a given surface the curvature vector K, associated with this curve, is
               the vector sum of the normal curvature κ (n) bn and geodesic curvature κ (g) bu and lies in a plane which
               is perpendicular to the tangent vector to the given curve on the surface. The geodesic curvature κ (g) is
               obtained from the equation (1.5.25) and can be represented

                                                                                 !
                                                                                ~
                                                       ~
                                                      dT            dT ~       dT
                                               ~                ~          ~
                                      κ (g) = bu · K = bu ·  =(bn × T) ·  =  T ×   · bn.
                                                      ds            ds         ds
               Substituting into this expression the vectors
                                          d~      du    dv
                                           r
                                      ~
                                               r
                                                      r
                                      T =    = ~ u  + ~ v
                                          ds      ds    ds
                                     dT ~           0 2                0 2
                                           ~
                                                              0
                                                                0
                                                                                      00
                                        = K = ~ uu (u ) +2~r uv u v + ~r vv (v ) + ~r u u + ~r v v ,
                                                                                00
                                               r
                                     ds
               where  0  =  d  , and by utilizing the results from problem 10 of the exercises following this section, we find
                         ds
               that the geodesic curvature can be represented as

                                 2     0 3       2       1       0 2
                                                                     0
                        κ (g) =      (u ) + 2        −         (u ) v +
                                 11              12      11
                                                                                                      (1.5.48)

                                2        1         0 2    1     0 3                p
                                                                                            2
                                                0
                                                                                0
                                                                         00
                                                                       0
                                                                              00
                                    − 2        u (v ) −       (v ) +(u v − u v )     EG − F .
                               22        12              22
               This equation indicates that the geodesic curvature is only a function of the surface metrices E, F, G and
                              0
                                    00
                                 0
               the derivatives u ,v ,u ,v . When the geodesic curvature is zero the curve is called a geodesic curve. Such
                                       00
               curves are often times, but not always, the lines of shortest distance between two points on a surface. For
               example, the great circle on a sphere which passes through two given points on the sphere is a geodesic curve.
               If you erase that part of the circle which represents the shortest distance between two points on the circle
               you are left with a geodesic curve connecting the two points, however, the path is not the shortest distance
               between the two points.
                   For plane curves we let u = x and v = y so that the geodesic curvature reduces to
                                                                      dφ
                                                            00
                                                          0
                                                    k g = u v − u v =
                                                                   0
                                                                 00
                                                                      ds
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