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Hamilton-Jacobi equation                                           69

                2.5    Hamilton-Jacobi equation

                We now discuss the connection between finding stationary points of the func-
                tionals I and J considered in the preceding sections and solving a first order
                partial differential equation known as Hamilton-Jacobi equation.This equation
                also plays an important role in the fields theories developed in the next section
                (cf. Exercise 2.6.3).
                   Let us start with the main theorem.

                                         1
                Theorem 2.17 Let H ∈ C ([a, b] × R × R), H = H (x, u, v).Assume that
                                2
                there exists S ∈ C ([a, b] × R), S = S (x, u), a solution of the Hamilton-Jacobi
                equation
                                S x + H (x, u, S u )= 0, ∀ (x, u) ∈ [a, b] × R ,  (2.14)
                                                                              1
                where S x = ∂S/∂x and S u = ∂S/∂u. Assume also that there exists u ∈ C ([a, b])
                asolutionof
                              u (x)= H v (x, u (x) ,S u (x, u (x))) , ∀x ∈ [a, b] .  (2.15)
                               0
                Setting
                                          v (x)= S u (x, u (x))                 (2.16)
                             1
                                       1
                then (u, v) ∈ C ([a, b]) × C ([a, b]) is a solution of
                                   ⎧
                                       u (x)= H v (x, u (x) ,v (x))
                                        0
                                   ⎨
                                                                                (2.17)
                                   ⎩   0
                                      v (x)= −H u (x, u (x) ,v (x)) .
                                                                        2
                Moreover if there is a one parameter family S = S (x, u, α), S ∈ C ([a, b] × R × R),
                solving (2.14) for every (x, u, α) ∈ [a, b] × R × R, then any solution of (2.15)
                satisfies
                               d
                                 [S α (x, u (x) ,α)] = 0, ∀ (x, α) ∈ [a, b] × R ,
                               dx
                where S α = ∂S/∂α.
                Remark 2.18 (i) If the Hamiltonian does not depend explicitly on x then every
                solution S (u, α) of
                         ∗
                                           ∗
                                     H (u, S )= α, ∀ (u, α) ∈ R × R             (2.18)
                                           u
                leads immediately to a solution of (2.14), setting

                                                   ∗
                                      S (x, u, α)= S (u, α) − αx .
                   (ii) It is, in general, a difficult task to solve (2.14) and an extensive bibliog-
                raphy on the subject exists, cf. Evans [43], Lions [69].
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