Page 51 - Introduction to Naval Architecture
P. 51

38                   FLOTATION AND STABILITY

          Referring to Figure 4.7 for the small angles being considered BBi =
        BM<f> and BM= //?. Thus the height of the metacentre above the centre
        of buoyancy is found by dividing the second moment of area of the
        waterplane about its centreline by the volume of displacement. The
        height of the centre of buoyancy above the keel, KB, is the height of the
        centroid of the underwater volume above the keel, and hence the
        height of the metacentre above the keel is:

             KM. = KB + BM

        The difference between KM and .KG gives the rnetacentric height,
        GM.


        Transverse metacentre for simple geometrical forms
         Vessel of rectangular cross section
        Consider the form in Figure 4.8 of breadth B and length L floating at
        draught T. If the cross section is uniform throughout its length, the
        volume of displacement = LBT.
          The second moment of area of waterplane about the centreline =
        LBV 12. Hence:





        Height of centre of buoyancy above keel, KB = 7/2 and the height of
        metacentre above the keel is:
























        Figure 4.8 Rectangular section vessel
   46   47   48   49   50   51   52   53   54   55   56