Page 84 - MATLAB an introduction with applications

MATLAB Basics ——— 69

Solution:
(a) A = [4 –1 5; 2 1 3; 6 –7 9]
A =
4 –1 5
2 1 3
6 –7 9
%The eigenvalues of A
format short e
eig(A)
ans =
1.0000e + 001
5.8579e – 001
3.4142e + 000
%The eigenvectors of A
[Q,d]=eig(A)
Q =
–5.5709e – 001 – 8.2886e – 001 – 7.3925e – 001
–3.7139e – 001 – 3.9659e – 002 – 6.7174e – 001
–7.4278e – 001 5.5805e – 001 – 4.7739e – 002
d =
1.0000e + 001 0 0
0 5.8579e–001 0
0 0 3.4142e + 000
(b) A =
3 5 7
2 4 8
5 6 10
%The eigenvalues of A
format short e
eig(A)
ans =
1.7686e + 001
–3.4295e – 001 +1.0066e + 000i
–3.4295e – 001 –1.0066e + 000i
%The eigenvectors of A
[Q,d]=eig(A)
Q =
Column 1
5.0537e – 001
4.8932e – 001
7.1075e – 001

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