Page 352 - Marks Calculation for Machine Design
P. 352

P1: Sanjay
                          January 4, 2005
                                      15:14
        Brown.cls
                 Brown˙C08
                  334
                                           APPLICATION TO MACHINES
                  then solve for (P bolt ) to give

                                                   k bolt
                                        P bolt =            P                  (8.34)
                                               k bolt + k members
                    If a joint constant (C) is defined as
                                                   k bolt
                                           C =                                 (8.35)
                                               k bolt + k members
                  then (1 − C) is therefore
                                               k bolt       k members
                                 1 − C = 1 −           =                       (8.36)
                                           k bolt + k members  k bolt + k members
                    Using the definition of the joint constant (C), the portion of the load carried by the bolt
                  (P bolt ) given in Eq. (8.34) becomes simply
                                               P bolt = CP                     (8.37)
                  and using the definition of (1−C), the portion of the load carried by the members (P members )
                  given in Eq. (8.32) becomes simply
                                           P members = (1 − C)P                (8.38)
                    Therefore, the total load on the bolt (F bolt ) is the portion of the load (P) carried by the
                  bolt (P bolt ) plus the preload (F preload ) and given by Eq. (8.39) as
                                    F bolt = P bolt + F preload = CP + F preload  (8.39)
                    Similarly, the total load on the members (F members ) is the portion of the load (P) carried
                  by the members (P members ) minus the preload (F preload )and given by Eq. (8.40) as
                               F members = P members − F preload = (1 − C)P − F preload  (8.40)
                  where the total force on the members (F members ) must remain negative to make sure the
                  joint does not separate, that is,
                                              F members < 0                    (8.41)
                    Experimental results indicate that the members can carry as much as 80 percent of the
                  external load (P), and therefore the bolt only carries 20 percent of the load.
                    Consider the following example using the stiffnesses of the bolt and members found in
                  Examples 1 and 2.


                            U.S. Customary                       SI/Metric
                  Example 3. Using the stiffness of the bolt  Example 3. Using the stiffness of the bolt
                  (k bolt ) found in Example 1 and the stiffness of  (k bolt ) found in Example 1 and the stiffness of
                  the members (k members ) found in Example 2,  the members (k members ) found in Example 2,
                  determine the joint constant (C), where  determine the joint constant (C), where
                                  6
                                                                    8
                      k bolt = 3.03 × 10 lb/in           k bolt = 4.66 × 10 N/m
                                                                    9
                                  6
                    k members = 9.04 × 10 lb/in        k members = 1.47 × 10 N/m
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