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86               Chapter 3                                             Matrix Algebra
                   Example 3.2.1

                                    Consider two springs that are connected as shown in Figure 3.2.1.


                                                     Node 1       k 1   Node 2   k 2      Node 3


                                                   x 1                 x 2                  x 3




                                                      F 1    -F 1             -F 3   F 3
                                                                  Figure 3.2.1
                                    The springs at the top represent the “no tension” position in which no force is
                                    being exerted on any of the nodes. Suppose that the springs are stretched or
                                    compressed so that the nodes are displaced as indicated in the lower portion
                                    of Figure 3.2.1. Stretching or compressing the springs creates a force on each
                                                               18
                                    node according to Hooke’s law  that says that the force exerted by a spring
                                    is F = kx, where x is the distance the spring is stretched or compressed and
                                    where k is a stiffness constant inherent to the spring. Suppose our springs have
                                    stiffness constants k 1 and k 2 , and let F i be the force on node i when the
                                    springs are stretched or compressed. Let’s agree that a displacement to the left
                                    is positive, while a displacement to the right is negative, and consider a force
                                    directed to the right to be positive while one directed to the left is negative.
                                    If node 1 is displaced x 1 units, and if node 2 is displaced x 2 units, then the
                                    left-hand spring is stretched (or compressed) by a total amount of x 1 −x 2 units,
                                    so the force on node 1 is
                                                               F 1 = k 1 (x 1 − x 2 ).
                                    Similarly, if node 2 is displaced x 2 units, and if node 3 is displaced x 3 units,
                                    then the right-hand spring is stretched by a total amount of x 2 − x 3 units, so
                                    the force on node 3 is
                                                              F 3 = −k 2 (x 2 − x 3 ).
                                    The minus sign indicates the force is directed to the left. The force on the left-
                                    hand side of node 2 is the opposite of the force on node 1, while the force on the
                                    right-hand side of node 2 must be the opposite of the force on node 3. That is,

                                                                F 2 = −F 1 − F 3 .
                                 18
                                    Hooke’s law is named for Robert Hooke (1635–1703),an English physicist,but it was generally
                                    known to several people (including Newton) before Hooke’s 1678 claim to it was made. Hooke
                                    was a creative person who is credited with several inventions,including the wheel barometer,
                                    but he was reputed to be a man of “terrible character.” This characteristic virtually destroyed
                                    his scientific career as well as his personal life. It is said that he lacked mathematical sophis-
                                    tication and that he left much of his work in incomplete form,but he bitterly resented people
                                    who built on his ideas by expressing them in terms of elegant mathematical formulations.
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