Page 261 - Mechanics Analysis Composite Materials

246 Mechanics and analysis of composite materials

and

(5.58)

Introduce a new coordinate of an arbitrary point A in Fig. 5.1 1 as z = t - (h/2).
Changing t for z we can present Eq. (5.29) in the form

Substituting these integrals into Eqs. (5.57) and (5.58) we get

(5.59)

and

(5.60)

where

hI2
JL'= J Allddz (5.61)

-hi2
and r = 0, 1,2.
Now decompose All as a function of z into symmetric and antisymmetric
components, i.e.,

Fig. 5.1 1. Coordinate of point A referred to the middle plane.