Page 245 - Modeling of Chemical Kinetics and Reactor Design
P. 245

Reaction Rate Expression  215

                              and


                                 K =  k 1  =  C 2 HS
                                  1             2                                       (3-342)
                                     k − 1  p  H 2  C S


                                              3
                                              S
                                 K =   k 3  =  CC NH S                                  (3-343)
                                                   3
                                  3
                                      k − 3  C NS  C 3 HS

                                 K =  k 4  =  Cp
                                             SNH 3
                                  4
                                     k − 4  C NH S                                      (3-344)
                                                3
                                From Equation 3-343, the concentration of the most abundant
                              surface intermediate is

                                        3
                                      CC   HN S
                                        s
                                 C NS  =     3                                          (3-345)
                                        KC  3
                                         3  HS
                              The concentration of adsorbed ammonia from Equation 3-344 is

                                        Cp
                                 C    =   SNH 3
                                  NH S    K 4                                           (3-346)
                                    3

                              The concentration of adsorbed hydrogen from Equation 3-342 is

                                  HS (         S) 12
                                               2
                                 C   =  K p  H 2  C                                     (3-347)
                                         1
                                Substituting Equations 3-346 and 3-347 into Equation 3-345 gives

                                            3
                                          CC p
                                            S
                                 C NS  =       S NH 3  32                               (3-348)
                                            (
                                                    2
                                       KK K p   H 2  C S)
                                              1
                                        3
                                           4
                                       p   C S
                                     =  NH 3                                            (3-349)
                                           .
                                        Kp 15
                                           H 2
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