Page 91 - Modeling of Chemical Kinetics and Reactor Design
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Thermodynamics of Chemical Reactions   61
                                                                 =
                                      ∂ U         ∂ U        ik  ∂ U 
                                 dU =         dS +         dV +  ∑             dn       (2-5)
                                      ∂ S         ∂ V            ∂ n         i
                                            ,
                                                         ,
                                                                          ,,
                                           Vn i         S n i    i=1   i  SV n j ,  i j ≠
                                If the number of moles are held constant, then from Equation 2-3
                                  ∂U    =          ∂U    =−
                                   ∂S     T   and     ∂V    p                         (2-6)
                                                          ,
                                       ,
                                      Vn i               S n i
                                The chemical potential µ  is defined by
                                                        i

                                       ∂U 
                                 µ ≡
                                      ∂n 
                                  i                                                     (2-7)
                                         i
                                            ,,
                                           SV n j
                                Equation 2-5 thus becomes
                                 dU =  TdS − pdV + ∑ µ i dn i                             (2-8)

                                                  i=1
                                The Gibbs function is expressed as:


                                G = U + pV – TS                                           (2-9)

                                Differentiating Equation 2-9 gives

                                dG = dU + pdV + Vdp – TdS – SdT                          (2-10)

                                Substituting Equation 2-3 into Equation 2-10 yields

                                dG = TdS – pdV + pdV + Vdp – TdS – SdT                   (2-11)

                                dG = Vdp – SdT                                           (2-12)

                                Since Equation 2-12 holds for a system of constant composition, it
                                is expressed as

                                G = G(T, P, n , n  . . . n                               (2-13)
                                             1   i      k)
                                Partial differentiation of Equation 2-13 gives
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