Page 94 - Modeling of Chemical Kinetics and Reactor Design
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64    Modeling of Chemical Kinetics and Reactor Design

                                Thus, for any small reversible displacement at equilibrium, dG = 0,
                              if dP = 0, dT = 0. Similarly:


                                If dT = 0, dV = 0 then dA = 0
                                If dP = 0, dS = 0 then dH = 0
                                If dV = 0, dS = 0 then dU = 0

                                               REACTION EQUILIBRIUM


                                Considering any generalized reversible chemical reaction, such that
                              at dT = 0 and dP = 0:

                                aA + bB [ cC + dD                                        (2-27)
                                If the reaction mixture is large enough that the mole numbers
                              corresponding to the stoichiometric numbers react, then the composi-
                              tions remain unchanged. If these mole numbers react at equilibrium,
                              then the overall change in Gibbs function is

                                dG = cµ  + dµ  – aµ – bµ  = 0     at equilibrium         (2-28)
                                                    A
                                        C
                                              D
                                                          B
                              Since
                                      ∂ G
                                 µ =     A
                                  A    n ∂  A                                            (2-29)
                                The chemical potential as a function of composition can be
                              expressed as

                                 µ =  µ + RT ln  a i                                     (2-30)
                                      o
                                      i
                              where a  is the activity of i. Introducing Equation 2-30 into the change
                                     i
                              in the Gibbs statement, and separating the standard state terms on the
                              right side, gives

                                       c
                                      a • a d D     o      o     o      o
                                       C
                                 RT ln       =−   c { µ C  +  dµ D  −  aµ A  −  bµ B}    (2-31)
                                       a
                                      a • a b B
                                       A
                                                                          
                                               
                                  c
                                 a • a d        −  c ( µ o C  +  dµ o D  − aµ o A  − bµ o B)
                                  C  D  =  exp                           
                                  a
                                 a • a b B                RT                           (2-32)
                                                                          
                                               
                                  A
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