Page 192 - Modelling in Transport Phenomena A Conceptual Approach
P. 192

172           CHAPTER 6.  STEADY-STATE MACROSCOPIC BALANCES


            where  CA,,,   and  cB,,  represent  the molar  concentrations  of species d and  t3 in
            the reactor, respectively. Dropping the subscript  “sys”  and dividing Eq.  (1) by the
            volumetric flow rate, Q, gives

                                            (CA)in - CA
                                        7=                                      (2)
                                              k CACB
            Using Eq.  (5.3-17), the extent of reaction can be  calculated m




                                   - (2000) (0.8)  = 1600 mol/ m3
                                   -
                                          1                                     (3)
            Therefore, the concentrations of species d, t3, and C  in the reactor are
                                     +
                          CA  = (cA)~~ QA < = 2000 - 1600 = 400 mol/ m3          (4)
                          CB  = (c~)in + (YB = 2400 - 1600 = 800 mol/ m3         (5)
                          cc  = (%)in  + ac [ = (2)(1600) = 3200 mol/ m3         (6)

            If kl and kz represent the rate constants at temperatures of TI and T2, respectively,
            then



            Therefore, the reaction rate constant at 65°C (338K) is

                                                       - -
                                                           -
                            k  = 8.4 x 10-6exp  - -
                                             [  ?E (3&?      2k)]
                             = 9.15 x     m3/ mol. min
            Substitution of numerical values into Eq.  (2) gives
                                        2000 - 400
                              7=                        = 54.6min
                                  (9.15 x     (400)(800)


            b) The reactor volume, V, is given by


            The volumetric pow rate can be  determined from the production rate of  species C,
            a.e..
                                                   820
                          ccQ=820       +     &=--     - 0.256 m3/ min
                                                  3200
            Hence, the reactor volume is

                                    V = (54.6)(0.256) = 14m3
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