Page 25 - Modelling in Transport Phenomena A Conceptual Approach
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6                                        CHAPTER 1.  INTRODUCTION

            surroundings through the boundaries of  the system.  In either case, the rate of
            input and/or  output of a quantity is expressed by using the flux of that particular
            quantity. The flux of  a quantity may be either constant or dependent on position.
            Thus, the rate of a quantity can be determined as

                                 [ (Flux)(Area)  if  flux is constant

               Inlet/Outlet  rate =                                          (1.3-1)
                                       Flux dA  if flux is position dependent


            where A is the area perpendicular  to the direction of  the flux.  The differential
            areas in cylindrical and spherical coordinate systems are given in Section A.l  in
            Appendix A.


            Example  1.3  Note  that  the  velocity  can  be  interpreted  as the  volumetric flux
            ( m3/m2. s).  Therefore, volumetric flow rate  can be  calculated  by  the  integration
            of  velocity  distribution  over  the  cross-sectional  area  that  is perpendicular  to the
            flow direction.  Consider the flow of a very viscous fluid in the space between two
            concentric  spheres  as  shown  in Figure  1.1.  The velocity  distribution  is given  by
            Bird et al.  (1960) as


                            Ue =
                                 2 pCLE(c) sin 0
            where
                                      E(€) = ln (       )
                                                1 +cos€
                                                1-cose

            Use the velocity profile to find the volumetric flow rate, &.

            Solution

            Since  the velocity is in the 0-direction,  the differential area that is perpendicular
            to the flow direction is given by Eq.  (A.l-9) in Appendix A  as
                                        dA = r sin 0 drdq5                       (1)

            Therefore,  the volumetric flow rate is
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