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9.3.  HEAT TRANSFER WITH CONVECTION                                 371

           Therefore, the first approximation to the Nusselt number is

                                         /'a1  - t2I2fl(t) e

                                 Nu(1) =                                   (9.3-68)
                                         1' ((1 - t2)f,2(t) ds

           Substitution of  f1(()  from Eq. (9.3-67) into Q. (9.3-68) and evaluation of  the
           integrals gives
                                          NU = 3.663                       (9.3-69)
           On the other hand, the value of the Nusselt number, 8s calculated by Graetz (1883,
           1885) and later independently by Nusselt (1910), is 3.66. Therefore, for a thermally
           developed laminar flow in a circular pipe with constant wall temperature Nu = 3.66
           for all practical purposes.

           Example 9.8  Water flows through a circular pipe of  5 cm internal diameter with
           an average velocity of 0.01 m/s. Determine  the length of  the pipe  to increase the
           water temperature from 20 "C to 60 "C for the following  conditions:
           a) Steam  condenses  on the  outer  surface  of  the  pipe  so  as to  keep  the  surface
           temperature  at  100 "C.
           b) Electrical  wires  are wrapped  around  the outer surface  of  the pipe  to provide  a
           constant wall heat flux of  1500 W/ m2.

           Solution
           Physical properties
              The mean bulk temperature is (20 + 60)/2 = 40 "C (313 K).
                                  p = 992 kg/ m3
                                  p = 654 x     kg/ m. s
              For water at 313 K :
                                    = 632   10-3  wl
                                                   m.
                                  Pr = 4.32
           Assumptions
             1.  Steady-state  conditions prevail.

             2.  Flow b hydrodynamically and thermally fully developed.
           Analysis

              The Reynolds number is



                         - (0.05) (0.01) (992)
                         -                 = 758    3      Laminar flow
                              654 x
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